He should have $5.25 left to spend on a card.
Hope This Helps! :3
So, f(x) is a composite function. This means that g(x) is inside of h(x); in other words, you would substitute g(x) for x in h(x).
Something happened to g(x) (in the form of h(x)) to turn it into f(x). You should notice that f(x) is simply g(x) raised to the third power.
Therefore, h(x) = x^3
You can check this by working it backwards.
Start with: h(x) = x^3
Substitute: x = g(x) = 4x^2-11
Now you have: h(x) = (g(x))^3 = (4x^2-11)^3
Hope this helps!
300words/min
1min= 60 secs
300words/60secs= 5
5words/second is your answer
21x+35y you have to distribute the outside number into the ones in the inside. Instagram: duiliobandzzz ; )
Answer:
Please check the explanation.
Step-by-step explanation:
<u>Even Functions:</u>
The function is unchanged when it is reflected about the y-axis.
i.e.
f(-x) = f(x)
<u>Odd Functions:</u>
The function is unchanged when it is rotated 180° about the origin.
i.e.
f(-x) = -f(x)
<u>Neither Functions:</u>
f(-x) ≠ -f(x)
Let us check the given functions:
plug –x in for x
f(-x) = V(-x)²9
f(-x) = Vx²9
f(-x) = f(x)
Therefore, the function f(x) = Vx²9 is even function.
plug –x in for x
as

and

so
f(-x) ≠ f(x)
f(-x) ≠ -f(x)
Thus,
g(x) = |x-3| is neither an even nor an odd function.
plug –x in for x
g(-x) = (-x) + (-x)²
g(-x) = -x + x²
g(-x) = -(x-x²)
so
f(-x) ≠ f(x)
f(-x) ≠ -f(x)
Thus, it is neither an even nor an odd function.
Thus,
g(x) = x + x² is neither an even nor an odd function.