Answer:
3rd graph down
Step-by-step explanation:
greens are x and carrots are y in my equations
2x - y >= 3
x + 2y < 4
The first equation is solid and will highlight everything to the right of it because it is a >
the second is dashed and will highlight everything to the left of it because it is a <
the only 2 graphs that show this are 1 and 3
looking at the points you can see that the points for the solid line are both the same so ignore those and go to the dashed lined ones.
on the first graph the points are (0,4)
plugging those into our equation gives us 0 + 2*4 <4
or 8<4 which doesnt make sense making 3 the correct graph
(sorry my answer wasnt posting so i had to start over and make it less detailed, but comment if you need any explanation)
Answer:
50x-2
Step-by-step explanation:
The system is:
i) <span>2x – 3y – 2z = 4
ii) </span><span>x + 3y + 2z = –7
</span>iii) <span>–4x – 4y – 2z = 10
the last equation can be simplified, by dividing by -2,
thus we have:
</span>i) 2x – 3y – 2z = 4
ii) x + 3y + 2z = –7
iii) 2x +2y +z = -5
The procedure to solve the system is as follows:
first use any pairs of 2 equations (for example i and ii, i and iii) and equalize them by using one of the variables:
i) 2x – 3y – 2z = 4
iii) 2x +2y +z = -5
2x can be written as 3y+2z+4 from the first equation, and -2y-z-5 from the third equation.
Equalize:
3y+2z+4=-2y-z-5, group common terms:
5y+3z=-9
similarly, using i and ii, eliminate x:
i) 2x – 3y – 2z = 4
ii) x + 3y + 2z = –7
multiply the second equation by 2:
i) 2x – 3y – 2z = 4
ii) 2x + 6y + 4z = –14
thus 2x=3y+2z+4 from i and 2x=-6y-4z-14 from ii:
3y+2z+4=-6y-4z-14
9y+6z=-18
So we get 2 equations with variables y and z:
a) 5y+3z=-9
b) 9y+6z=-18
now the aim of the method is clear: We eliminate one of the variables, creating a system of 2 linear equations with 2 variables, which we can solve by any of the standard methods.
Let's use elimination method, multiply the equation a by -2:
a) -10y-6z=18
b) 9y+6z=-18
------------------------ add the equations:
-10y+9y-6z+6z=18-18
-y=0
y=0,
thus :
9y+6z=-18
0+6z=-18
z=-3
Finally to find x, use any of the equations i, ii or iii:
<span>2x – 3y – 2z = 4
</span>
<span>2x – 3*0 – 2(-3) = 4
2x+6=4
2x=-2
x=-1
Solution: (x, y, z) = (-1, 0, -3 )
Remark: it is always a good attitude to check the answer, because often calculations mistakes can be made:
check by substituting x=-1, y=0, z=-3 in each of the 3 equations and see that for these numbers the equalities hold.</span>
Answer:
Option C.
Step-by-step explanation:
In △ONM and △SRQ,
We need to find the value of x that will make △ONM similar to △SRQ by the SAS similarity theorem.
According to SAS similarity theorem, two triangle are similar if two corresponding sides in both triangles are proportional and the included angle in both are congruent.
It is given that . So, both triangles are similar by SAS if
Substitute the given values.
Divide both sides by 8.
Therefore, the correct option is C.
Line CA is a straight line, meaning it adds up to 180°
Line BE splits the line into two supplementary angles, because when the two angles are added together they will equal 180°
Using the rule of supplementary angles, we can then make the equation 3x + 8x + 15 = 180
Now, simplify the equation by combining like terms
11x + 15 = 180
To solve, isolate x
11x + 15 = 180
11x = 165
x = 15
