Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:


*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
Answer:300,000
Step-by-step explanation: if the 4 was a 5 or higher then the answer would’ve been 400,00 but since the number next to the underlined digit is 4 then it goes to 300,00. (4 or below leave it alone 5 or above give it a shove)
Answer:
Hi!
First you would start at -4 on the x-axis, then you would move up 3 spaces and put your point there.
The x-axis is the horizontal line, and the y-axis is the vertical line.
I hope this helps you!
Answer:
It subtracts
Step-by-step explanation:
Answer:
237 pounds
Step-by-step explanation:
237 pounds