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2 years ago

R+10<-3(2r-3)+6(r+3)

Mathematics

1 answer:

MAVERICK [17]2 years ago

8 0

Answer:

{r:r<17}

Step-by-step explanation:

given r+10<-3(2r-3)+6(r+3)

change the < to = to solve the equation

thus, r+10=-3( 2r-3 )+6( r+3 )

r+10= -6r +9 +6r +18

r+10= 9+18

r+10=27

r=27-10

r=17

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R+10<-3(2r-3)+6(r+3)​

R+10<-3(2r-3)+6(r+3)