Answer:
807.8 in^2
Step-by-step explanation:
The total area of the box is the sum of the areas of all faces of the box. The top, bottom, front, and back faces are rectangles 18 in long. The end faces each consist of a rectangle and a triangle. We can compute the sum of these like this:
The areas of top, bottom, front, and back add up to be 18 inches wide by the length that is the perimeter of the end: 2·5in +2·8 in + 9.6 in = 35.8 in. That lateral area is ...
(18 in)(35.6 in) = 640.8 in^2
The area of the triangle on each end is equivalent to the area of a rectangle half as high, so we can compute the area of each end as ...
(9.6 in)(8.7 in) = 83.52 in^2
Then the total area is the lateral area plus the area of the two ends:
640.8 in^2 + 2·83.52 in^2 = 807.84 in^2 ≈ 807.8 in^2
To factor, we always have to look for common factors in the numbers given to us. In this case, in 1/2 and 6, the common factor is 1/2. Therefore, we will have to factor like so:
1/2d + 6 = 1/2 (d + 3)
Hope this helps!
The correct answer is 23/6. Hope this helps.
Answer:
7. C(N(h))=33hx+460h
8. about $13.94 is the cost
Step-by-step explanation:
7. C(x)=(33x+460)(N(h))=(N(40)h)--C(x)=(33x+460)(40h)--C(x)=1320hx+18400h--simplified to C(N(h))=33hx+460h
8. C(N(10))=33(10)x+460(10)--C(N(10))=330x+4600--4600/330=about13.94
Answer:
C
Step-by-step explanation:
-5.5-11.2
change the subtraction to addition
5.5+11.2= 16.7
