3x⁶y² + 57x⁵y³ + 252x⁴y⁴
= 3x⁴y²(x² + 19xy + 84y²)
= 3x⁴y²(x² + 12xy + 7xy + 84y²)
= 3x⁴y²(x(x + 12y) + 7y(x + 12y))
= 3x⁴y²(x + 12y)(x + 7y)
Answer:
x^2-4x+y^2+6y-108=0
Step-by-step explanation:
The answer to the question is 2:3
answer:
set 4
Step-by-step explanation:
because when you divide the numbers 12,16 and 20 by 2 you'll get 6,8 and 10 which is a Pythagoras family....and it will form a right angle triangle