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3 years ago

What is the standard form of the equationCenter (-14,5), circumference: 22π

Mathematics

1 answer:

IRISSAK [1]3 years ago

6 0

The standard equation for a circle with center at (h,k) and radius r is

(x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle.

The formula for the circumference of a circle is C = 2pi*r. In this particular problem, we need to determine the radius of the circle. That radius is: r = C/[2pi]. Here, C = 22pi, so we get r = 22pi/[2pi], and so r^2 = 11^2.

Putting to use the given info, we have:

(x+14)^2 + (y-5)^2 = 11^2

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jeyben [28]

Answer:

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Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

4x−15>−2x+15

Step 2: Add 2x to both sides.

4x−15+2x>−2x+15+2x

6x−15>15

Step 3: Add 15 to both sides.

6x−15+15>15+15

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Step 4: Divide both sides by 6.

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3 years ago

10 is 1/10 percent of what number? The answer key says 1,000. Can you please explain why? Thank you.

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The key lies in translating "1/10 percent." If the unknown number is n, then 0.001n = 10. Mult. both sides by 1000: n = 10000 (answer)

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3 years ago

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What is the common ratio of the geometic sequence whose second and forth terms are 6 and 54, respectively?

Luda [366]

Answer:

Step-by-step explanation:

The n th term formula of a geometric sequence is

$a_{n}$ = a $r^{n-1}$

where a is the first term and r the common ratio

Using the second and fourth term, then

ar = 6 → (1)

ar³ = 54 → (2)

Divide (2) by (1)

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netineya [11]

Answer:

B. x = -1 ± i

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Standard Form: ax² + bx + c = 0
Factoring
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define

x² + 2x = -2

Step 2: Identify Variables

Rewrite Quadratic in Standard Form [Addition Property of Equality]: x² + 2x + 2 = 0
Break up Quadratic: a = 1, b = 2, c = 2

Step 3: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-2 \pm \sqrt{2^2-4(1)(2)}}{2(1)}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-2 \pm \sqrt{4-4(1)(2)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-2 \pm \sqrt{4-8}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-2 \pm \sqrt{-4}}{2}$
[√Radical] Factor: $\displaystyle x=\frac{-2 \pm \sqrt{-1}\sqrt{4}}{2}$
[√Radicals] Simplify: $\displaystyle x=\frac{-2 \pm 2i}{2}$
Factor: $\displaystyle x=\frac{2(-1 \pm i)}{2}$
Divide: $\displaystyle x = -1 \pm i$

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3 years ago