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Airida [17]
3 years ago
14

What is the standard form of the equationCenter (-14,5), circumference: 22π

Mathematics
1 answer:
IRISSAK [1]3 years ago
6 0

The standard equation for a circle with center at (h,k) and radius r is

(x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle.

The formula for the circumference of a circle is C = 2pi*r.  In this particular problem, we need to determine the radius of the circle.  That radius is:  r = C/[2pi].  Here, C = 22pi, so we get r = 22pi/[2pi], and so r^2 = 11^2.

Putting to use the given info, we have:

(x+14)^2 + (y-5)^2 = 11^2

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OR (in more details):


(-\dfrac{3^2}{3^3} )^2 = (-3^{2-3})^2 = (-3^{-1})^2 = (-\dfrac{1}{3} )^2 = \dfrac{1}{9}


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Line\ passing\ through\ (-1.5,0)\ and\ (0,2).\\\\Correct\ graph\ is\ attached.

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The\ given\ equation\ represents\ a\ line\\\\

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