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4 years ago

What is 8.203 × 10^-15

1 answer:

3 0

If you would like to solve 8.203 * 10^(-15), you can do this using the following step:

1 * 10^(-15) = 0.000000000000001

8.203 * 10^(-15) = 8.203 * 0.000000000000001 = 0.000000000000008203

The correct result would be 0.000000000000008203.

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Point P is located at (-5,-1) and point Q is located at (-1,-7).find the slope of line segment PQ.

gayaneshka [121]

Point A (x1,y2) = (-1, -7)

Point B (x2,y2) = (-5, -1)

Objective :

Find the slope of a line that passes through points A and B.

Formula :

Slope

$m= \frac{y2-y1}{x2-x1}$

Solution:

Slope (m) = $\frac{-1-(-7)}{5-(-1)}$

=6 - 4

m = -1.5

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4 years ago

Please help with problem !!

melisa1 [442]

Answer:

Step-by-step explanation:

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3 years ago

Health club 560 per year $50 down payment how much will 12 equal payments be

lara [203]

Answer:

$42.5

Step-by-step explanation:

560-50=510 510 divided by 12=42.5

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3 years ago

If the answer is L * W * H then why do you have to divide once you get to H to get the correct answer?

Kisachek [45]

Answer:

Hi! I'm not quite sure what you entirely mean by this but I'll try to help. LxWxH is a formula used to find the volume of a rectangular prism or a box. If this is what you are using it for then there shouldn't a reason to divide. Unless maybe you're trying to find half of a box or you are trying to find the value of one of these in an equation but that's the only thing I can think of. Do you think you might be able to post an example in the comments?

Step-by-step explanation:

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3 years ago

The circumference of a sphere was measured to be 74 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the ma

larisa86 [58]

Answer Step-by-step explanation:

Circumference of sphere=74 cm

Error=0.5 cm

a.We know that circumference of sphere= $C=2\pi r$

Using the formula

$74=2\pi r$

$r=\frac{74}{2\pi}=\frac{37}{\pi}$

$C=2\pi r$

Differentiate w.r.t r

$\frac{dC}{dr}=2\pi$

$dC=2\pi dr$

$dr=\frac{dC}{2\pi}=\frac{0.5}{2\pi}$

Surface area of sphere= $S=4\pi r^2$

Maximum area in the surface area= $dS=8\pi rdr$

$dS=8\pi\times \frac{37}{\pi}\times \frac{0.5}{2\pi}=23.5\approx 24 cm^2$

Hence,the maximum area in the surface area=24 square cm

Relative error= $\frac{\Delta S}{S}\approx \frac{dS}{S}$

$\frac{\Delta S}{S}=\frac{8\pi rdr}{4\pi r^2}=2\frac{dr}{r}=2\times \frac{\frac{0.5}{2\pi}}{\frac{37}{\pi}}=2\times \frac{0.5}{2\pi}\times \frac{\pi}{37}=0.014$

Hence, the relative error=0.014

8 0

3 years ago