Answer:
0.44290869
Step-by-step explanation:
The Maclaurin series for sin⁻¹(x) is given by
sin⁻¹(x) = x +
Use the first five terms of the Maclaurin series above to approximate sin⁻¹ . (Round your answer to eight decimal places.)
Answer
sin⁻¹(x) = x +
in the above equation summation from n=1 to ∞
we are estimating this for the first 5 terms as follows
sin⁻¹(x) = x + + + +
sin⁻¹(x) = x + + + +
now to get
sin⁻¹() substitute
hence,
sin⁻¹() =
sin⁻¹() = 0.42857142 + 0.01311953 + 0.00108437 + 0.00011855 + 0.00001482
= 0.44290869
-1/5 would be your answer for this problem.
Answer:
D. 1-2i is your answer.
Step-by-step explanation:
What you're doing is adding them together.
<em>4 + -3 + -7i + 5i = 1-2i</em>
D. 1-2i is your answer.
Answer:
C
Step-by-step explanation:
This is because the line was growing starting form the y-int=2.
Now the line is decreasing starting from y-int=2.
First I will present the polynomial itself: it is
5x^3 - 22x^2 - 3x - 53.
Let's show that when this poly. is divided by (x-5), the quotient is 5x^2 + 3x + 12 and the remainder is 7. Use synthetic division here. Let the divisor be 5 (this comes from the factor (x-5). Then:
__________________
5 / 5 -22 -3 -53
25 15 60
----------------------------
5 3 12 7 where 5 3 12 are the coeff. of the quotient and 7
is the remainder.
Now work backwards. Multiply (x-5) and (5x^2 + 3x + 12) together. We get
5x^3 + 3x^2 + 12 x - 25x^2 - 15x - 60, or
5x^3 - 22x^2 - 3x - 60. Now add the remainder (7) to -60; the result will be -53.
So the poly in question is 5x^3 - 22x^2 - 3x - 53.