In this exercise we have to observe the axes of the graph to associate the values of X with those of Y that correspond to 0, 5, 5, -3, -5, -3, 2, 0, 0, -1, -2, 1, 1, -1, -1, -2, 2, 3, -1.
<h3>How to calculate the Cartesian plane?</h3>
Just draw two lines: one of them vertical, starting from the point until it finds the x axis; another horizontal, starting from the point until it meets the y-axis.
Then plotting the value of X on the graph we find the following for each value of X to Y:
- X= 0 ; Y= 0;
- X= 1 ; Y= 5;
- X= 2 ; Y= 5;
- X= 3 ; Y= -3;
- X= 4 ; Y= -5;
- X= 5 ; Y= -3;
- X= 6 ; Y= 2;
- X= 7 ; Y= 0;
- X= 8 ; Y= 0;
- X= 9 ; Y= -1;
- X= 10 ; Y= -2;
- X= 11 ; Y= 1;
- X= 12 ; Y= 1;
- X= 13 ; Y= -1;
- X= 14 ; Y= -1;
- X= 15 ; Y= -2;
- X= 16 ; Y= 2;
- X= 17 ; Y= 3;
- X= 18 ; Y= -1;
See more about coordinates at brainly.com/question/23450276
This is called in physics refraction phenomenon.
It occurs when light when the light passes from one medium with density d1 to another medium with density d2. The sight of the archer travel from air to deep into water & provokes a refraction.
Answer:
The answer is Option A
Explanation:
Cup of milk m = 299 mg
Cup of juice j = 261 mg
Limit of intake = 1000mg
Total amount of calcium from milk = 299 × m = 299m mg
Total amount of calcium from juice = 261 × j = 261j mg
Since it must be equal to or exceeding the daily limit u use the GREATER THAN OR EQUAL TO SIGN.
299m + 261j <u>></u> 1000
The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
Learn more about Tension calculations : brainly.com/question/24994188
