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schepotkina [342]
3 years ago
5

What is the difference in kilowatt hours of monthly energy production between an average local wind speed of 15 miles per hour a

nd an average local wind speed of 10 miles per hour? I really just need a SIMPLE answer! Not an entire break down...
Mathematics
2 answers:
nirvana33 [79]3 years ago
8 0

Answer:

The difference in kilowatt hours of monthly energy production between an average local wind speed of 15 miles per hour and an average local wind speed of 10 miles per hour would be of a third less kilowatts produced with a 10 miles per hour wind than with a 15 miles per hour wind.

Step-by-step explanation:

This is because 10 corresponds to 2/3 of 15, 1/3 being the remaining value of electrical production that would not be generated with a wind of 10 mph rather than a 15 mph wind.

natali 33 [55]3 years ago
6 0

Answer:

the difference is 5

Step-by-step explanation:

difference means subtraction meaning you subtract 15-10 and your answer would be 5 <em>your welcome</em>

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Answer: A(t)=-8t+52

Step-by-step explanation:

<h3> The missing question is: "What is the Functions formula A(t)=?"</h3><h2 />

The  equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

According to the data given in the exercise, you know that:

- A(t) represents the area to paint the Hiros' romm as a function of time.

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Therefore, based on this, you can idenfity that:

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So you must substitute the slope and the coordinates of that point into y=mx+b and then solve for "b" in order to find its value:

28=-8(3)+b\\\\28+24=b\\\\b=52

Therefore, you can determine that the function A(t) is:

A(t)=-8t+52

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