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schepotkina [342]
3 years ago
5

What is the difference in kilowatt hours of monthly energy production between an average local wind speed of 15 miles per hour a

nd an average local wind speed of 10 miles per hour? I really just need a SIMPLE answer! Not an entire break down...
Mathematics
2 answers:
nirvana33 [79]3 years ago
8 0

Answer:

The difference in kilowatt hours of monthly energy production between an average local wind speed of 15 miles per hour and an average local wind speed of 10 miles per hour would be of a third less kilowatts produced with a 10 miles per hour wind than with a 15 miles per hour wind.

Step-by-step explanation:

This is because 10 corresponds to 2/3 of 15, 1/3 being the remaining value of electrical production that would not be generated with a wind of 10 mph rather than a 15 mph wind.

natali 33 [55]3 years ago
6 0

Answer:

the difference is 5

Step-by-step explanation:

difference means subtraction meaning you subtract 15-10 and your answer would be 5 <em>your welcome</em>

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I need the work shown not just the answers please
Yuliya22 [10]
1.) To find the surface area, we want to find the area of each side, then add them all up together:
Area of base=lwA=(5)(5)A=25 cm²
Area of triangle=1/2bhA=(1/2)(5)(12.5)A=31.25 cm²
Since the 4 triangles have the same area, we can multiply the area we found by 4 and then add the area of the square:
SA=(4)(31.25) + 25SA=125+25SA=150 cm²

2.) <span>To find the volume use the formula: 

V=(1/3)lwh
V=(1/3)(5)(5)(12.5)
V=104.167 cm^3</span>
3 0
3 years ago
Can you find the midpoint of AB​
Masteriza [31]
Use the distance formula for the 2 points and then halve the answer
7 0
2 years ago
Read 2 more answers
What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of
notsponge [240]

Answer:

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

Step-by-step explanation:

The question is as following:

The verticies of a triangle on the coordinate plane are

A(0, 0), B(2, 0) and C(0, 2).

What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of 1/3 ?

=============================================

Given: the vertices of a triangle ABC are A(0, 0), B(2, 0) and C(0, 2).

IF the triangle is dilated by a factor of k about the origin, then

(x,y) → (kx , ky)

that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

It is given that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

If a figure dilated by a factor of 1/3 about the origin

So, (x,y)\rightarrow (\frac{1}{3}x,\frac{1}{3}y)

<u>So, The coordinates of the triangle A'B'C' are:</u>

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

6 0
3 years ago
68.76−5.23<br><br> A 16.46<br><br> B 18.53<br><br> C 63.53<br><br> D 73.99
Romashka [77]
The answer is 63.53 subtracts 5.23 from 68.76


6 0
3 years ago
Read 2 more answers
Helppppp meeeeee:)))))))))))))))))))))))) ​
Vikki [24]

Answer:yes

Step-by-step explanation:

is so yes so if the 50 it was the 40 so then they it yes

3 0
2 years ago
Read 2 more answers
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