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3 years ago

15

Milena's take-home pay is $1200 a month. She spends 12% of her take-home pay on her cable bill. How much is Milena's monthly cab

le bill?

2 answers:

inna [77]3 years ago

3 0

$1200 - 12% = $144

1200 - 144 = $1056

12% = 1056

ad-work [718]3 years ago

3 0

Answer:

144

Step-by-step explanation:

apex

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95-a(b+c) when a=9, b=3, c =7.4

AleksAgata [21]

Answer:

95-9 (3+7)

95-9 (10)

86 (10)

= 8600

Step-by-step explanation:

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3 years ago

Find the areas of the shaded regions.

diamong [38]

Answer:

41.8887 cm^2

Step-by-step explanation:

area of a circle
A = pi * r^2
A = pi * (3 + 4)^2
A = pi * 49
A = 153.94

120 / 360 = 1/3
153.94 / 3 = 51.3134

now area of inner circle
A = pi * 3^2
A = pi * 9
A = 28.274
28.274 / 3 = 9.4247

subtract
51.3134 - 9.4247 = 41.8887

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2 years ago

TIMED TEST PLEASE ANSWER ASAP!!?!?!??!?!?!? PLZZ DONT ANSWER IF U DONT KNOW IT!!!!!!!!!!!!!

sashaice [31]

Answer:

I would say plane XYN

Step-by-step explanation:

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3 years ago

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

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3 years ago

Which equation represents the graphed line? linear graph y=5

schepotkina [342]

y=-2x+5

Hope that helps :D

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3 years ago