Answer:
Width of the rectangle = 5 inches
Length of the rectangle = 20 inches
Step-by-step explanation:
Let us assume the width of the rectangle = m in
So, the length of the rectangle = 4 (Width) = (4 m) in
Perimeter of the rectangle = 50 inches
Now, Perimeter of the Rectangle = 2 (LENGTH + WIDTH)
⇒ 2( m + 4m) = 50
or, 2(5m) = 50
⇒ 10m = 50 or, m = 50/10 = 5
⇒ m = 5
So, the width of the rectangle = 5 inches
and the length of the rectangle = 4 m = 4 x 5 = 20 inches
Answer: (2,2)
Step-by-step explanation:
I'm going to use substitution to solve this:
First, I use the second equation to solve for y in terms of x.
2x - y = 2
-y = 2 - 2x
y = 2x - 2
Then, I plug the value for y into the first equation:
2x + 4y = 12
2x + 4(2x - 2) = 12
2x + 8x - 8 = 12
10x - 8 = 12
10x = 20
x = 2
Now that we have x, we can plug it into either equation (I used the first) to get the value for y:
2x + 4y = 12
2(2) + 4y = 12
4 + 4y = 12
4y = 8
y = 2
We get the point (2,2) as a solution.
Note: This is the point where both lines intersect.
Answer:
the answer is 95
Step-by-step explanation:
you divide 90 by 36 to get 2.5 then times that by 38
Answer:
y = 30x + 20
Step-by-step explanation:
y = mx + b
find b
b=20
find m
m=30
