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ANTONII [103]
3 years ago
5

Graph y = 2x + 1 Help pleaee

Mathematics
2 answers:
jonny [76]3 years ago
7 0

Answer:

Step-by-step explanation:

qwelly [4]3 years ago
6 0

Answer:

Answer is linked

Step-by-step explanation:

The equation is in slope-intercept form, which is y = mx + b.

To graph the line, first we have to find the slope, m, and the y- intercept, b.

So, the slope is 2 and the y- intercept is 1.

We can graph this, beginning with the y- intercept, 1. The y- intercept is always on the y axis, so the (x) value will always be zero.

Plot a point at (0, 1).

Next, add more points using the slope. The slope is 2, or \frac{2}{1}. Start at the point we have made on the y axis. The slope equals the \frac{rise}{run}. We can rise 2 units, then run one more unit to the right. If the slope is negative, the run goes to the left. However, in this case, the slope is positive, to it slants to the right.

We end on point (1, 3). We can continue this path infinitely, some other points on the graph could be (2, 5), (3, 7), (4, 9) and (5, 11).

Connect these points to make a line.

The finished line is linked below as well.

I hope this helps :] Good luck ^^

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-1 + 4x=3x +3<br> Solve for x ?
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Answer:

x = 4

Step-by-step explanation:

1. Regroup terms.

4x  - 1 = 3x + 3

2. Add 1 to both sides.

4x = 3x + 3 + 1

3. Simplify 3x + 3 + 1 to 3x + 4.

4x = 3x + 4

4. Subtrect 3x from both sides.

4x - 3x = 4

5. Simplify 4x - 3x to x.

x = 4

Therefor, the answer is, x = 4.

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3 years ago
A real estate company wants to build a parking lot along the side of one of its buildings using 400 feet of fence. If the side a
svetlana [45]

Answer:

1.) Therefore the side parallel to the building is 100 feet.

2.) The side perpendicular to the building is 200 feet.

Step-by-step explanation:

The parking lot, which is rectangular,  is built along the side of one of its buildings.

The side of the parking lot which is alongside the building needs no fence,

let us say that this side is of length y.

Let the perpendicular to the building be of length x.

The perimeter of the parking lot that actually needs to be fenced  = 2x + y

The amount of fencing available  = 400 feet.

Therefore 2x + y = 400    ....    (i)

Therefore y = 400 - 2x     ....    (ii)

The area of the parking lot, A = xy   =   x ( 400 - 2x)  =   400x - 2x^2   ....   (iii)

Therefore \frac{dA}{dx}  = \frac{d(400x - 2x^2}{dx}  = 400 - 4x     ....   (iv)

Also we get \frac{d^2A}{dx^2}  = -4     ....    (v)

Hence we will get the maximum value of the parking lot by equating the first order differential of area, A to zero as the second order differential of area, A is negative.

Therefore from (iv) we get 400 - 4x  = 0     ∴ x = 100 feet

y  = 400 - 2x = 400 - 200 = 200 feet.

1.) Therefore the side parallel to the building is 100 feet.

2.) The side perpendicular to the building is 200 feet.

6 0
3 years ago
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