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lorasvet [3.4K]
3 years ago
8

Six rectangles each with a common base width of 2

Mathematics
1 answer:
Yuki888 [10]3 years ago
4 0
91 IS THE AREAS OF THE SIX RECTANGLES
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The graph below shows the distance, y, in miles, of a bird from its nest for a certain amount of time, x, in minutes:
Bogdan [553]

Answer:

<em>(d).</em>

Step-by-step explanation:

The y-intercept (0, 3) is initial value of graph ⇒ (d). <em>3 miles; it represents the original distance of the bird from its nest</em>

7 0
3 years ago
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Find the indicated term of the given arithmetic sequence. a1=45, d= -3, n=10
klasskru [66]

In this sequence, we're given the first term, which is 45.

The difference between each term is -3, which means 3 will be subtracted in each term.

We're asked to find the value of the tenth term, and we can do so by using this formula:

a(n) = a(1) + d(n - 1)

Replace values.

a(10) = 45 + -3(9)

a(10) = 18

<h3>The value of the tenth term is 18.</h3>
3 0
3 years ago
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Simply (2)/(3)a+6-(3)/(5)a-1
Bas_tet [7]

Answer:

That simplifies to \frac{1}{15}a + 5

Step-by-step explanation:

Let's simplify:

\frac{2}{3}a + 6 - \frac{3}{5}a - 1\\\\\frac{10}{15}a - \frac{9}{15}a + 6 - 1\\\\\frac{1}{15}a + 5

If you want to express that as a single fraction, you can do so by multiplying the five by 15/15, and summing the numerators.  That gives you:

\frac{a + 75}{15}

8 0
3 years ago
Prove that triangle with side lengths of x^2-1, 2x, x^2+1 is a right triangle.
Brrunno [24]
Right triangles must follow the pythagorean theorem, so a^2+b^2=c^2.

Let's find a^2 and b^2 by squaring the first 2 side lengths.

(x^2-1)^2= x^4-2x^2+1
(2x)^2= 4x^2

Then add the two to find c^2
x^4+ 2x^2 +1= c^2

Root both sides
x^2+1=c

Since the side lengths can be plugged into the pythagorean theorem, the side lengths must represent a right triangle.
Hope this helps!
7 0
3 years ago
Can someone answer theese 3 questions
RSB [31]

Answer:

Which three questions?

Step-by-step explanation:

I've answered this first question, I guess I need two more...

3 0
2 years ago
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