Since it is at least 3 means that the club must bring 3 or more ideas so x>=3 which is choice d
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Answers: x = -17 and x = 64</h3>
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Explanation
Consider three scenarios:
- A) The value of x is the smallest of the set (aka the min)
- B) The value of x is the largest of the set (aka the max)
- C) The value of x is neither the min, nor the max. So 8 < x < 39.
These scenarios cover all the possible cases of what x could be. It's either the min, the max, or somewhere in between the min and max.
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We'll start with scenario A.
If x is the min, then that must mean 39 is the max as it's the largest of the set {18, 36, 16, 39, 27, 8, 34}
The range is 56, so,
range = max - min
56 = 39 - x
56+x= 39
x = 39-56
x = -17 which is one possible answer
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If instead we go with scenario B, then x is the max and 8 is the min
range = max - min
56 = x - 8
56+8 = x
64 = x
x = 64 is the other possible answer
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Lastly, let's consider scenario C. If x is not the min or the max, then it's somewhere between the min 8 and max 39. in short, 8 < x < 39.
Note that range = max - min = 39-8 = 31 which is not the range of 56 that we want. So there's no way scenario C can be possible here.
It wouldn't play or else i would help
Answer:
D
Step-by-step explanation:
I think...this is a really hard question but D is the one I would choose. Forgive me if I'm wrong
Answer:
10 blocks
Step-by-step explanation:
South and West are perpendicular to each other, meaning they form a right angle. With the diagonal intersecting with each of the corners, we can form a right triangle. We can use Pythagorean Theorem (a^2 + b^2 = c^2) to find that 8^2 + 6^2 = (diagonal)^2. 8^2 + 6^2 = 100. The square route of 100 is 10, meaning Dana would have to walk 10 blocks.
