First and third, second can still be simplified.
Answer:
17w+35
Step-by-step explanation:
(2+2w)⋅4+9(w+3)
Distribute the 4 and the 9
2*4 + 2w*4 +9*w+9*3
8+8w +9w +27
Combine like terms
8w+9w +8+27
17w +35
Given:
A data set has a median of 12, an upper quartile of 15, a lower quartile of 10, a minimum of 4, and a maximum of 20.
To find:
The correct statement for the box plot.
Solution:
Lower quartile is 10 and upper quartile is 15, so the box will go from 10 to 15.
Median of the data set is 12, so a line dividing the box will be at 12.
Minimum value is 4 and lower quartile is 10, so the left whisker will go from 4 to 10.
Upper quartile is 15 and maximum value is 20, so the right whisker will go from 15 to 20.
Therefore, the correct option is B.
Answer:
Area Of a Right Angled∆
=><em><u> </u></em><em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>x </u></em><em><u>Base </u></em><em><u>x </u></em><em><u>Height</u></em>
Area of a ∆ Using Heron's Formula
=>
Where
- S = Semiperimeter
- a ,b& c = sides of the ∆
