The question above has multiple answers:
<span>1.
</span>Sort the data in the field "name of the
tool" in ascending order alphabetically.
<span>2.
</span> Sort the
data in the field “number of tools” in ascending order.
<span>3.
</span>Sort the data in ascending order of cost per
tool.
<span>4.
</span>Sort the data in ascending order of total cost.
The answer is 3. Sort the data in ascending order of cost
per tool
You can always make your spreadsheet work a bit more organized
by sorting your data. In this case, what is required from the manufacturer of
the tools is to sort the data so that someone else is able to find out which
tool costs the most. Basically, the price of the tool which is the highest is
required to be known. Therefore, the manufacturer of the tools should Sort the
data in ascending order of cost per tool.
Answer:
Network storage appliances
Explanation:
Because I just took a test
I think the correct answer among the choices given is option A. Manipulative aids are not technological aids. It refers to items that is used to support hands-on learning like markers, toothpick or coins. Technological aids, on the other hand, are things which makes use of the new technology present like slideshows, DVD's, audioclips and projectors.
Answer:
465 ways
Explanation:
Atleast 1 girl and 1 boy
Possible combinations :
1 girl ; 3 boys = 6C1 ; 6C3
2 girls ; 2 boys = 6C2 ; 6C2
3 girls ; 1 boy = 6C3 ; 6C1
(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)
Combination formula:
nCr = n! ÷ (n-r)!r!
We can also use a calculator :
6C1 = 6
6C3 = 20
6C2 = 15
Hence,
(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)
(6 * 20) + (15 * 15) + (20 * 6)
120 + 225 + 120
= 465 ways
Answer:
#include <iostream>
#include <cstdlib>
using namespace std;
int m, n;
void transpose(int matrix[]){
int transp[m][n];
for (int i = 0; i < n; i++){
for (int j = 0; j < m; j++){
transp[j][i] = matrix[i][j];
cout<< transp[j][i]<< " ";
}
cout<< "\n";
}
}
int main(){
cout<< "Enter the value for n: ";
cin>> n;
cout>> "Enter the value for m: ";
cin>> m;
int mymatrix[n][m];
for (int i = 0; i < n; i++){
for (int j = 0; j < m; j++){
mymatrix[i][j] = (rand() % 50);
}
}
transpose(mymatrix);
}
Explanation:
The C source code defined a void transpose function that accepts a matrix or a two-dimensional array and prints the transpose on the screen. The program gets user input for the row (n) and column (m) length of the arrays. The C standard library function rand() is used to assign random numbers to the array items.
