Find the number of ways in which a committee of 4 can be chosen from six boys and
1 answer:
Answer:
465 ways
Explanation:
Atleast 1 girl and 1 boy
Possible combinations :
1 girl ; 3 boys = 6C1 ; 6C3
2 girls ; 2 boys = 6C2 ; 6C2
3 girls ; 1 boy = 6C3 ; 6C1
(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)
Combination formula:
nCr = n! ÷ (n-r)!r!
We can also use a calculator :
6C1 = 6
6C3 = 20
6C2 = 15
Hence,
(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)
(6 * 20) + (15 * 15) + (20 * 6)
120 + 225 + 120
= 465 ways
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