"Consider the following cross:

Biology

1 answer:

ruslelena [56]4 years ago

3 0

The answer is <span>a.1/8</span>

<span>This is an example of Mendelian dihybrid cross (a cross between two different traits).
If:
Y - (dominant) allele for the first trait
r - (recessive) allele for the first trait
S - (dominant) allele for the second trait
s - (recessive) allele for for the second trait

</span>The cross will be like:

Parents: YyTt x YyTt

As shown in image, there will be in total 16 different genotypes. Two of them are YyTT genotypes. So the probability that the offspring will show YyTT genotype is 2 of 16:

= 2/16 = 1/8

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