All categories

4 years ago

If ten baseballs weight 1,417.4 grams how mush does one base ball weigh

Mathematics

2 answers:

Kobotan [32]4 years ago

5 0

141.74 grams is your answer

CaHeK987 [17]4 years ago

4 0

Since you have the total weight of all ten baseballs, divide the total amount by 10. So the equation is 1,417.4 divided by 10, which gives you the answer, 141.74. So each baseball weighs 141.74 grams.

You might be interested in

WILL GIVE BRAINLIST PLS HELP ME

marysya [2.9K]

Answer:

12. 5(5x+4)(5x-4)

13. 2(4v+5)(4v-5)

14. 5(3x+2)(3x-2)

Step-by-step explanation:

7 0

3 years ago

For the following right triangle, find the side length x.

never [62]

Answer:

x = 10

Explanation:

Using Pythagoras Theorem:

a² + b² = c²

Solve:

8² + 6² = x²

x² = 64 + 36

x² = 100

x = √100

x = 10

8 0

3 years ago

Read 2 more answers

In what ways does algebra act as a tol to improve communication? How does algebra affect how people can learn from each other

Serjik [45]

Answer:

it helps you in everyday life

Step-by-step explanation:

you can speak better

4 0

3 years ago

A research analyst for a car rental agency found that the probability distribution function for the age of the rental car (in ye

alexdok [17]

Answer:

10 years

Step-by-step explanation:

Given

Decline from (0,h) to (10,0)

See attachment for graph

Required

Determine the age when height = 0

The function of the graph is represented as: (age, height)

So, we need to read from the graph the corresponding value of age (on the x-axis) when height = 0 (i.e. the y-axis)

From the attached graph;

$age = 10$ when $height = 0$

<em>Hence, the age of the car is 10 years</em>

4 0

3 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

3 years ago