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3 years ago

Patty lives on a chicken farm and can collect 80 eggs in 2 hours. At that rate how long will it take her to collect 360 eggs?

Mathematics

2 answers:

LenKa [72]3 years ago

6 0

Answer:

9 hours

360/80 = 4.5 x 2 = 9

Mamont248 [21]3 years ago

3 0

Answer:

9 hours

Step-by-step explanation:

First we have to calculate how many eggs she can collect in an hour. All we have to do to do this is divide 80 by 2, as if she can collect 80 in 2 hours, in one hour, half of the time, she can collect have of the eggs. This means that she can collect 40 eggs in one hour.

Now all we have to do is divide how many eggs she wants to collect by how many she can collect per hour, which will give how many hours it will take. In this case 360/40=9, so it will take her 9 hours.

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A sample of 16 ATM transactions shows a mean transaction time of 67 seconds with a standard deviation of 12 seconds. State the h

Soloha48 [4]

Answer:

Null hypothesis: $\mu \leq 60$

Alternative hypothesis: $\mu > 60$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{67-60}{\frac{12}{\sqrt{16}}}=2.33$

Step-by-step explanation:

Data given and notation

$\bar X=67$ represent the sample mean

$s=12$ represent the population standard deviation for the sample

$n=16$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 60, the system of hypothesis would be:

Null hypothesis: $\mu \leq 60$

Alternative hypothesis: $\mu > 60$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{67-60}{\frac{12}{\sqrt{16}}}=2.33$

4 0

3 years ago

What number can be expressed as a nonrepeating, nonterminating decimal?

EastWind [94]

An irrational number.

Happy studying!

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3 years ago

Read 2 more answers

Can anyone else not see answers rn???

Fofino [41]

Yeah i cant see them either

7 0

2 years ago

The solution of the following equation as 0.15 ( 10t - 9= 0.75 (4t - 3)

Alenkinab [10]

Answer:

$\huge\boxed{\sf t = 0.6}$

Step-by-step explanation:

$\sf 0.15(10t-9) = 0.75(4t-3)\\\\Resolving \ Parenthesis\\\\1.5t-1.35 = 3t - 2.25\\\\Combining \ like \ terms\\\\-1.35 + 2.25 = 3t-1.5t\\\\0.9 = 1.5t\\\\Dividing \ both \ sides \ by \ 1.5\\\\0.9/1.5 = t\\\\0.6 = t\\\\OR\\\\\bold{t = 0.6}$