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4vir4ik [10]
4 years ago
10

The equation for this question.

Mathematics
1 answer:
just olya [345]4 years ago
8 0
We can solve this by setting up a system of equations. We will use x for the $3 boxes and y for the $5 boxes:

x+y=34
3x+5y=130

We can use the elimination method by multiplying the first equation by 3:

3x+3y=102
3x+5y=130

0x-2y=-28
y=14

We can then plug this number back into one of the original equations to solve for x:

x+14=34
x=20

We can check these answers by plugging them into the equations:

20+14=34
34=34

(3)(20)+(5)(14)=130
60+70=130
130=130

Therefore, there are 20 of the $3 boxes, since we originally said that x would be the $3 boxes.
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Least to greatest 63.37,62.95,63.7
Anit [1.1K]

Answer:

1.  62.95

2.  63.37

3.  63.7

Step-by-step explanation:

List the numbers by lining up the decimals and filling in zeros in the empty spaces to make all the numbers have the same number of digits,  then compare whole numbers first then the decimals.  There are two 63's so then you look at the decimal side one is .37 and one is .70 (add the zero so all numbers have the same number of digits)

63.37

62.95

63.70 (added the zero)

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\bf \cfrac{small}{large}\quad \stackrel{area~ratio}{\cfrac{s^2}{s^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{(5x)^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{5^2x^2}}\implies \stackrel{area~ratio}{\cfrac{\underline{x^2}}{25\underline{x^2}}}=\stackrel{area~ratio}{\cfrac{35}{a}}&#10;\\\\\\&#10;\cfrac{1}{25}=\cfrac{35}{a}\implies a=\cfrac{25\cdot 35}{1}
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