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4vir4ik [10]
4 years ago
10

The equation for this question.

Mathematics
1 answer:
just olya [345]4 years ago
8 0
We can solve this by setting up a system of equations. We will use x for the $3 boxes and y for the $5 boxes:

x+y=34
3x+5y=130

We can use the elimination method by multiplying the first equation by 3:

3x+3y=102
3x+5y=130

0x-2y=-28
y=14

We can then plug this number back into one of the original equations to solve for x:

x+14=34
x=20

We can check these answers by plugging them into the equations:

20+14=34
34=34

(3)(20)+(5)(14)=130
60+70=130
130=130

Therefore, there are 20 of the $3 boxes, since we originally said that x would be the $3 boxes.
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