Answer:
f(x)=(2x-7)^7(x+3)^4
When y=0, (2x-7)^7=0 and x=3.5 OR
(x+3)^4=0, and x=-3
Look at x=h or f(2)
That is 96-56-44+2 and it is not equal to 0. (x-2) is not a factor.
x^3-5x^2+6x-30
after trying 1,2, and 3, I tried 5
5/1===-5===6===-30
==1===0====6====30
(x^2-6) with no remainder
the factors are (x-5)(x^2+6)
the zeroes are 5, +/- i sqrt (6). Only one real 0.
hope this helps let me know in the comments if i'm wrong
8+16
If you want the answer it is 24.
You just plug it in.
You welcome
Answer:
The answer is B
Step-by-step explanation:
Hope this helped :D
Answer:
Leaving as a radical form
Why?
Because that's the whole value if you convert it to a decimal you cannot write all the numbers, and in the radical form it has all the numbers
It would be useful when we are working with equations for example the quadratic equation, if you get that x=√5, you would want the exact value. And there are more useful
