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4 years ago

Figure ABCD has vertices A(−3, 2), B(2, 2), C(2, −4), and D(−3, −2). What is the area of figure ABCD?

Mathematics

2 answers:

Sidana [21]4 years ago

8 0

Answer:

The area of the figure ABCD is $25\ units^{2}$

Step-by-step explanation:

we have

$A(-3, 2), B(2, 2), C(2, -4), D(-3, -2)$

using a graphing tool

Plot the figure

see the attached figure

The figure is a trapezoid

The area of the trapezoid is equal to

$A=\frac{1}{2}(AD+BC)AB$

Find the distance between the points in the graph

we have

$AD=4\ units$

$BC=6\ units$

$AB=5\ units$

substitute

$A=\frac{1}{2}(4+6)5=25\ units^{2}$

FromTheMoon [43]4 years ago

5 0

25 tried so pls give a thnx if right if wrong just give me a heads up! : )

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lyudmila [28]

Answer:

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Step-by-step explanation:

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