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lisabon 2012 [21]
3 years ago
15

Figure ABCD has vertices A(−3, 2), B(2, 2), C(2, −4), and D(−3, −2). What is the area of figure ABCD?

Mathematics
2 answers:
Sidana [21]3 years ago
8 0

Answer:

The area of the figure ABCD is 25\ units^{2}

Step-by-step explanation:

we have

A(-3, 2), B(2, 2), C(2, -4), D(-3, -2)

using a graphing tool

Plot the figure

see the attached figure

The figure is a trapezoid

The area of the trapezoid is equal to

A=\frac{1}{2}(AD+BC)AB

Find the distance between the points in the graph

we have

AD=4\ units

BC=6\ units

AB=5\ units

substitute

A=\frac{1}{2}(4+6)5=25\ units^{2}

FromTheMoon [43]3 years ago
5 0
25 tried so pls give a thnx if right if wrong just give me a heads up! : )
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