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coldgirl [10]
3 years ago
13

How do I solve for nr=5n+5w

Mathematics
2 answers:
lakkis [162]3 years ago
6 0
5n + 5w = r \\ \\ 5n = r - 5w \\\\ n =  \frac{r-5w}{5}
Serggg [28]3 years ago
3 0
R = 5n + 5w
r - 5w = 5n
r/5 - w = n
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Please help me with this dont guess pls!
dexar [7]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
This figure is the pre-image of a prism that has undergone a dilation with a scale factor of 3/4.
belka [17]

The surface area of the image after the dilation is 219 3/8 m²

<h3>What is an area?</h3>

Area is the amount of space occupied by a two dimensional shape or object.

The surface area of the prism = 2(0.5 * 5 * 12) + (5 * 11) + (11 * 12) + (13 * 11) = 390 m²

The surface area of the image after the dilation = scale factor² *  390 m² = (3/4)² * 390 m² = 219 3/8 m²

The surface area of the image after the dilation is 219 3/8 m²

Find out more on area at: brainly.com/question/25292087

5 0
2 years ago
Helppp it's timed
fomenos

Answer:

D.

Step-by-step explanation:

h(x)=f(x)g(x) means multiply the expression for f to the expression for g.

That is the problem is just asking you to do (11x-5)(-2x-4).

Let's use foil.

First:  11x(-2x)=-22x^2

Outer: 11x(-4)=-44x

Inner: -5(-2x)=10x

Last: -5(-4)=20

------------------------Add together!

-22x^2-34x+20

D.

6 0
3 years ago
In the isosceles triangle ABC, we have AB=AC=4. The altitude from B meets AC at H. If AH=3(HC) then determine BC.
Inga [223]

Answer:

BC=√7

Step-by-step explanation:

AC=4

AC=AH+HC

=3HC+HC

=4HC

HC=1/4AC=1/4×4=1

AH=3HC=3×1=3

BH⊥ AC

AB=AC=4

BC=\sqrt{AB^2-AH^2} =\sqrt{4^2-3^2} =\sqrt{16-9} =\sqrt{7}

5 0
3 years ago
sam decides to build a square garden if the area of the other garden is 9x^2 -24x +16 square feet what is the length of one side
Yuri [45]
<span>9x^2 -24x +16 can be factored into (3x-4)</span>²
the length of each side is 3x-4
4 0
4 years ago
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