#1 is 125
#3 is 1/2
#5 is the same as the question
#7 is 5p^3 over 3
#9 is 4/5
Answer: a) 0.0792 b) 0.264
Step-by-step explanation:
Let Event D = Families own a dog .
Event C = families own a cat .
Given : Probability that families own a dog : P(D)=0.36
Probability that families own a dog also own a cat : P(C|D)=0.22
Probability that families own a cat : P(C)= 0.30
a) Formula to find conditional probability :
(1)
Similarly ,

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792
b) Again, using (2)

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264
1. Subtract 4 from both sides
v - 4 = 2t
2. Divide both sides by 2
v - 4/2 = t
3. Switch sides
t = v - 4/2
The answer is 24 root 3 or 41.56921938.
Answer:
∠RUP is 135°
Step-by-step explanation:
First find the angle of QUR
QUS is 90 so you just subtract 45 from 90 and you get 45
QUP is also 90. Add 45 to it this time: 135