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Ghella [55]
3 years ago
15

A new Youth Activity Center is being built in Hadleyville. The perimeter of the rectangular playing field is 430 yards. The leng

th of the field is 5 yards less than quadruple the width. What are the dimensions of the
playing field?

The width is yards.

The length is yards.
Mathematics
1 answer:
scoundrel [369]3 years ago
8 0

Answer:

Width = 44 yards

Length = 171 yards

Step-by-step explanation:

Given:

<em>Perimeter of the rectangular field = 430 yards.</em>

Let:

<em>The length of the field be L</em>

<em>The width of the field be W.</em>

From the question:

<em>The length of the field is 5yards less than quadruple the width. This implies that;</em>

L = 4W - 5

But.

Perimeter (P) of a rectangle is given by:

P = 2(L + W)       ---------------(i)

Substitute the values of P = 430, L = 4W - 5 and W into equation (i) as follows;

430 = 2(4W - 5 + W)

430 = 2(5W - 5)

430 = 10W - 10

10W = 430 + 10

10W = 440

Divide both sides by 10

W = 44

Therefore, the width of the field is 44 yards.

Remember that,

L = 4W - 5          

[Now substitute W = 44]

L = 4(44) - 5

L = 176 - 5

L = 171

Therefore, the length of the field is 171 yards

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