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xeze [42]
3 years ago
15

Which lake has a surface area that is 14938 square miles greater than the surface area of Lake Ontario draw a model and write a

number sentence to show the problem
Mathematics
1 answer:
stellarik [79]3 years ago
7 0
I I know is that it would be lake michigan
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Evaluate the expression for the given value of the variable(s). Show your work.
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I got -50 as my answer
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Solve the following equations. Show your work. Submit to your teacher when you have completed the sheet.
DochEvi [55]

Answer:

1. y=3  

2.x=4

3. k= -2

4.n= -45

5. c = -3

6. p = 4

7. t = 0

8. r = \frac{3}{4}

Step-by-step explanation:

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3 years ago
15x+12(10-x)=141<br>make sure to use steps to solve!​
goldfiish [28.3K]

Answer: x=7

Step-by-step explanation: First you distribute the 12 to (10-x). That then gives you 15x+120-12x=141. Now you combine like terms. So you do 15x-12x=3x. Your new equation now is 3x+120=141. Subtract 120 from 141 and mark it out. That leaves you with 3x=21. Divide both sides by 3. Your final answer is x=7.

5 0
3 years ago
The 2014 Community College Survey of Student Engagement (CCSSE) included a question that asked faculty how much of their coursew
Kisachek [45]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the courses emphasize memorizing facts, ideas or methods following the same distribution as before.

The variable of interest is

X: Opinion of students in how much of their coursework emphasized memorizing facts, ideas, or methods. Categorized: 1_"Very little", 2_" Some", 3_" Quite a bit" and 4_"Very much"

It is known for a survey made in 2014 that the percentages for each category are: 1_Very little: 21.5%, 2_Some: 33.7%, 3_Quite a bit: 27.7% and 4_Very much: 17.1%

To test if the current situation follows the same distribution as the historical data (from 2014) you have to conduct a Goodness to Fit Chi-Square test.

The hypotheses are:

H₀: P₁= 0.215; P₂= 0.337, P₃= 0.277 and P₄= 0.171

H₁:

α: 0.01

X^2= sum[\frac{(O:i-E_i)^2}{E_i} ]~~X^2_{k-1}

k= number of categories of the variable.

This test is always one-tailed (right), which means that you will reject the null hypothesis to high values of X² (when the observed and expected frequencies for each category are too different)

The critical value is:

X^2_{k-1;1-\alpha }= X^2_{3;0.99}= 11.345

You will reject the null hypothesis if X^2_{H_0} \geq  11.345

You will not reject the null hypothesis if X^2_{H_0} < 11.345

Before calculating the statistic under the null hypothesis, you have to calculate the expected value for each category following the formula:

E_i= n*P_i

n= 400

E₁= n*P₁= 400*0.215= 86

E₂= n*P₂= 400*0.337= 134.8

E₃= n*P₃= 400*0.277= 110.8

E₄=n*P₄= 400*0.171= 68.4

The observed frequencies are:

O₁= 39

O₂= 139

O₃= 148

O₄= 74

X^2_{H_0}= (\frac{(39-86)^2}{86} )+(\frac{(139-134.8)^2}{134.8} )+(\frac{(148-110.8)^2}{110.8} )+(\frac{(74-68.4)^2}{68.4} )= 38.76

As said before, this test is one-tailed to the right (always) and so is its p-value:

P(X₃²≥38.76)= 1 - P(X²₃<38.76)= 1 - 1 ≅ 0

p-value < 0.00001

Using both approaches (p-value and critical value) the decision is to reject the null hypothesis.

With a level of significance of 1% the decision is to reject the null hypothesis, then the actual courses do not emphasize the memorization of facts, ideas, and methods following the historical percentages.

I hope this helps!

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4 years ago
PLEASE HELP --Which of the following best describes the figure?
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I believe it is a Concave pentagon
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