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xeze [42]
3 years ago
10

The inverse of f(x)=(x-2)^2

Mathematics
2 answers:
algol [13]3 years ago
7 0
That the answer x^2-4x+4
Rama09 [41]3 years ago
3 0
The answer I believe is X^2-4X+4
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F(x)=5x-3 find the domain and range
lakkis [162]

Answer:

Let's solve for f.

fx=5x−3

Step 1: Divide both sides by x.

fx

x

=

5x−3

x

f=

5x−3

x

Let's solve for x.

fx=5x−3

Step 1: Add -5x to both sides.

fx+−5x=5x−3+−5x

fx−5x=−3

Step 2: Factor out variable x.

x(f−5)=−3

Step 3: Divide both sides by f-5.

x(f−5)

f−5

=

−3

f−5

x=

−3

f−5

Answer:

x=

−3

f−5

Step-by-step explanation:

Hope I helped

8 0
3 years ago
Read 2 more answers
G varies inversely with the square
vivado [14]

Answer:;4.4

Step-by-step explanation: Since it varies inversely we know G times H squared is equal to some constant, k. So we have G*H*H=k. We are told that when H=4, G=.25. Plugging this in, we have .25*4*4=k. This simplifies to 4=k. Our new equation is G*H*H=4. Now, we want to solve for G when H=.3. We plug it in. G*.3*.3=4 => G*.09=4. G=4/.09. This means G is approximately 44.4.

5 0
3 years ago
Read 2 more answers
Approximate 589.57 to the nearest whole number..​
n200080 [17]

Answer:

590.00

Step-by-step explanation:

Im guessing SORRY

8 0
3 years ago
PLEASE HELP ME If 0 < z ≤ 90 and sin(9z − 1) = cos(6z + 1), what is the value of z? z = 3 z = 4 z = 5 z = 6
Burka [1]

Answer:

  z = 6

Step-by-step explanation:

We know that ...

  sin(x) = cos(90 -x)

Substituting (9z-1) for x, this is ...

  sin(9z -1) = cos(90 -(9z -1))

But we also are given ...

  sin(9z -1) = cos(6z +1)

Equating the arguments of the cosine function, we have ...

  90 -(9z -1) = 6z +1

  90 = 15z . . . . . . . . . add (9z-1) to both sides

  6 = z . . . . . . . . . . . . divide by 15

_____

<em>Comment on the graph</em>

The attached graph shows 5 solutions in the domain of interest. These come from the fact that the relation we used is actually ...

  sin(x) = cos(90 +360k -x)  . . . . .  for any integer k

Then the above equation becomes ...

  90 +360k = 15z

  6 +24k = z . . . . . . . . . for any integer k

The sine and cosine functions also enjoy the relation ...

  sin(x) = cos(x -90)

  sin(9z -1) = cos(9z -1 -90) = cos(6z +1)

  3z = 92 . . . . . equating arguments of cos( ) and adding 91-6z

  z = 30 2/3

6 0
3 years ago
Y=6xy = 5x + 7 substitution
Naddik [55]

Answer:

Step-by-step explanation:

hello :

y=6x...(*)

y = 5x + 7...(**)

by (*) put the value of y in(**) :

6x=5x+7

6x-5x=7

x=7   but  y=6x   so : y=42

the system solution is (7,42)

7 0
3 years ago
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