Answer:
<h3>x = 4</h3>
Step-by-step explanation:
102 + 102 + 24x + 24x - 18 - 18 = 360
204 + 48x - 36 = 360
204 + 48x = 360 + 36
204 + 48x = 396
48x = 396 - 204
48x = 192
x = 192/48
x = 4
Answer:
too freaking small dude
Step-by-step explanation:
Answer: 
r=26
Step-by-step explanation:
Given: Mrs. Morton rewards her students on behave well by putting 3 marbles into a marble jar.
If the jar contains 24 marbles. and r represent the number of additional times the class is rewarded then the required equation will be
If we solve it, we will get the minimum the jar contains 24 marbles.
To solve equation, subtract 24 from both sides, we get
Hence, the minimum whole number of additional times they need to be rewarded so they can have a party=26
Answer:
2b^2
Step-by-step explanation:
according to the question equation is
(a^2 + b^2 ) - (a^2 - b^2)
a^2 + b^2 - a^2 + b^2
plus a square and minus a square gets cancel
b^2 + b^2
since they are like terms they can be added
2b^2
Reminder: the formula for a geom. seq. is
a(n) = a(1)*r^(n-1), where a(1) is the first term, n is the counter and r is the common ratio.
I first noted that 243 is a power of 3; specifically, 243=3^5, or 243=3(3)^4, or 243=(3^2)(3)^(4-1). Notice that I'm trying here to rewrite 243=3^5 in the form a(n) = a(1)*r^(n-1): a(4) = a(1)(3)^(4-1), or a(4) = a(1)(3)^3 = 243. Then by division we find that a(1) = 243/27 = 9. Is it possible that a(1)=9?
Let's try out our formula a(n)=9(3)^(n-1). Steal n=9 and see whether this formula gives u s 59049:
n(9) = 59049 = 9(3)^(9-1), or 9(3)^8. True or false? 3^8= 6561, and 9(3)^8 = 59049.
YES! That's correct.
Therefore, the desired formula is
a(n) = 9(3)^(n-1). The first term, a(1) is 9(3)^(1-1) = 9(3)^0 = 9*1 = 9.
