Question

If a+b+c=9 and ab+bc+ca=23 then a^3+b^3+c^3-3abc =?

Answer 1

Answer:

Step-by-step explanation:

a³  +b³ + c³ - 3abc =(a +  b + c)(a² + b² + c² - [ab+bc+ac] )

                              =  9 (a² + b² + c²- 23)