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vekshin1
3 years ago
5

If a+b+c=9 and ab+bc+ca=23 then a^3+b^3+c^3-3abc =?

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0

Answer:

Step-by-step explanation:

a³  +b³ + c³ - 3abc =(a +  b + c)(a² + b² + c² - [ab+bc+ac] )

                              =  9 (a² + b² + c²- 23)

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