If a+b+c=9 and ab+bc+ca=23 then a^3+b^3+c^3-3abc =?

1 answer:

5 0

Answer:

Step-by-step explanation:

a³ +b³ + c³ - 3abc =(a + b + c)(a² + b² + c² - [ab+bc+ac] )

= 9 (a² + b² + c²- 23)

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