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3 years ago

Jorge asked each of the 24 students in his class if they play a musical instrument. He also asked each

Mathematics

1 answer:

HACTEHA [7]3 years ago

4 0

Answer:

Here's what I get.

Step-by-step explanation:

I have highlighted the given information in the table below.

Here's how I got the other numbers

1. Students who don't play a sport

Total students = 24

Students who play a sport = 14

Students who don't play a sport = 10

2. Students who play a sport but not music

Play a sport = 14

Play a sport and music = 6

Play sport but not music = 8

3. Students who play music but not a sport

Don't play a sport = 10

Play neither music nor sport = 3

Play music but not sport = 7

4. Total who play music

Play both music and sport = 6

Play music but not sport = 7

Total who don't play music = 13

5. Total who don't play music

Play a sport but not music = 8

Play neither sport nor music = 3

Total who don't play music = 11

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The high temperature is forecast to be 5.4 F . What is this temperature in degrees Celsius ()?

AleksAgata [21]

Answer:

-14c

Step-by-step explanation:

I’m using the actual values 1F = -17C so just times that by 5.4

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3 years ago

What is the slope of the line that passes through the points (7.-12) and (-9,36)?

REY [17]

Answer:

Step-by-step explanation:

m = slope where

m = rise / run

rise = y2 - y1

run = x2 - x1

where

the given point P1 = (7, -12)

and is in the form of (x1,y1)

and

the given point P2 = (-9,36)

is in the form of (x2,y2)

then

m = ( y2 - y1 ) / ( x2 - x1 )

m = ( 36 - (-12) ) / ( -9 -7 )

m = ( 36 + 12 ) / ( - 16 )

m = 48 / - 16

m = - 3

the slope is negative 3

slope = - 3

4 0

3 years ago

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

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