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Arisa [49]
3 years ago
12

Figure B is a scaled copy of Figure A.

Mathematics
1 answer:
algol133 years ago
6 0

Answer: Scale factor = 2

=====================================================

Explanation:

Pick on any pair of corresponding sides. I'll pick the right-most sides of each figure. For figure A, that would be the side of 40 units. Figure B has this corresponding side be 80 units long.

The scale factor is 80/40 = 2. This shows that figure B has sides 2 times longer compared to the corresponding sides on figure A.

So in short all you do is divide the corresponding side lengths. We divide in the format (figureB)/(figureA) because of the transition from A to B, and not the other way around.

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Invention cost three dollars for a pack of eight. Laura gives the cashier $20 to buy inventions and gets $11 and change. How man
brilliants [131]
Laura buys 3 packs of inventions.
 
20-11=9
(amount given-change=actual cost)

9 ÷ 3 = 3
(actual cost ÷ dollars per pack= number of packs bought)


4 0
3 years ago
X * 2 - 21<br><br><br> x + 12<br><br><br> x - 12<br><br><br> x * 2 - 17
BaLLatris [955]

Answer:

The functions is;

x - 12

Step-by-step explanation:

Input is (x)

(2) - 12 = -10

(6) - 12 = -6

(10) - 12 = -2

(5) - 12 = -7

3 0
3 years ago
What is the solution to -122 &lt; -3(-2-8x) -8x
Mariulka [41]

Answer:

x>-8

Step-by-step explanation:

-122<-3(-2-8x)-8x

-122<6+24x-8x

-128<16x

x>-8

5 0
3 years ago
Which value of x makes the equation x + 0.5x = x + 6 true?<br><br> 3<br> 12<br> 6<br> 30
zhenek [66]
The answer for this would be x=12
6 0
3 years ago
Find the average rate of change of each function over the interval [0, 2]. Match each representation with its respective average
marishachu [46]
Average rate of change over interval [a,b]: r=[f(b)-f(a)]/(b-a)
In this case the interval is [0,2], then a=0, b=2
r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2

1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
r=4

2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
r=(0+10)/2
r=(10)/2
r=5

3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
g(0)=2
r=(6-2)/2
r=(4)/2
r=2

4) Fourth function: j(x)
r=[j(2)-j(0)]/2
From the table:
x=2→j(2)=-8
x=0→j(0)=4
r=(-8-4)/2
r=(-12)/2
r=-6

Answer:
Pairs
1) h(x)     4
2) f(x)      5
3) g(x)     2
4) j(x)     -6
8 0
3 years ago
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