Question

How do i solve 13-4x=1-x

Answer 1

You need to isolate all the unknowns on one side and the numbers on the other.
So: 
Adding 4x to both sides to cancel the (-4x) on the LHS gives:
13 = 1 -x + 4x
Now takeaway one to cancel the one on the RHS:
13 - 1 = 4x -x
12 = 3x  Now divide by the times of x
x = 12/3
x = 4
Hope that helped!

Answer 2

13-4x=1-x
13=1+3x
3x=12
x=4