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shepuryov [24]
3 years ago
13

4x-3=2(3+x-1) what is the answer?

Mathematics
2 answers:
mart [117]3 years ago
7 0

Answer:

4x-3=2(3+x-1)

4x-3=6+2x-2

4x-2x=6-2+3

2x=7

x=7/2

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

lesantik [10]3 years ago
5 0
4x - 3 = 2(3+x-1)
4x - 3 = 6 +2x - 2
4x - 2x = 6 - 2 + 3
2x = 7
x = 7/2
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Tina says that 6:8 is equivalent to 36:64 . what did tina do wrong!
serious [3.7K]
She simplified it wrong because you're only supposed to simplify it with the same numbers. For example: simplify 2/4. You divide it by 2/2. You do the same and it will be correct.
8 0
3 years ago
Read 2 more answers
I need help I just got this today no clue how to do it it’s due tomorrow btw
Alisiya [41]

Answer:

i am REALLLYYY not sure about my answer but i think its 6. i dont recommend you to put that answer in lol

Step-by-step explanation:

6 = 3/3

7 0
3 years ago
The nth term = 1x2^n-1 find the 7th term
maw [93]
7th term: 1*2^(6)
=64
6 0
3 years ago
The angle t is acute and sin t = 6/7 is given use a Pythagorean identity to find cos t
Dennis_Churaev [7]

Answer:

sqrt(1 - 36/49) = +root(13)/7

Step-by-step explanation:

sin^2t + cos^2t is identical to 1 for all t.

(6/7)^2 + cos^2t = 1

1 - 36/49 = cos^2t

hence plus/miuns sqrt(1 - 36/49) = cos(t)

since t is acute, the answer must be positive.

7 0
3 years ago
Someone please help. If you could possibly show your work or tell me what you did that would be wonderful. Thanks!
alexandr1967 [171]
Start by getting all of your stuff on the same side.
(4x^2 - 1)/2y - (9y - 5)/3 - z+3y = 0

Then, move the (4x^2 - 1)/2y to the other side of the equation by subtracting it from both sides.
- (9y - 5)/3 - z+3y  = -(4x^2 - 1)/2y

Next, get all your ys on the same side of the equation. To do this, multiply both sides by 2y.
2y * (- (9y - 5)/3 - z+3y ) = -(4x^2 - 1)

Simplify this out.
(-18y^2 - 10y)/3 - 2yz +6y^2 = -(4x^2 - 1)

(-18y^2 - 10y)/3 is equal to  -6y^2 - 10y/3, so the equation can be rewritten as
-6y^2 - 10y/3 - 2yz +6y^2 = -(4x^2 - 1)
The 6y^2 and -6y^2 cancel eachother out and equal zero.
- 10y/3 - 2yz  + 0 = -(4x^2 - 1)

Now we have to move z over. To do this, factor out a y from each term.
y(-10/3 - 2z) =  -(4x^2 - 1)

Now, all we have to do is divide both sides by (-10/3 - 2z) to get
y = -(4x^2 - 1)/(-10/3 - 2z)

If we simplify this out, we will find that it is equal to
y = -3(4x^2 - 1)/(-10 - 6z)  = -3(4x^2 - 1)/-2(5 + 3z) = 3(4x^2 - 1)/2(5 + 3z)
y = 3(4x^2 - 1)/2(3z + 5)

The answer is D.


5 0
3 years ago
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