A nonlinear system of equation is a system of equation that has at list one nonlinear equation
A nonlinear system of equations that has one linear function that never intersects the quadratic function has; <u>No solution</u>
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The reason the option selected for the number of solutions is correct is as follows;
Required:
The number of solutions a system of nonlinear equations that do not intersect have
Solution:
The given system of equation is presented as follows;
Linear function: f(x) = m·x + c
Quadratic function: f(x) = a·x² + b·x + c
Given that the linear function never touches the quadratic function, we have;
a·x² + b·x + c ≠ m·x + c
Therefore, the equations are never equal hand they have no common solution
Therefore, the correct option is <u>No solution</u>
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Learn more about nonlinear system of equations here:
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Wait what is this? Is this supposed to be something
Answer:
0.4
Step-by-step explanation:
Slope-intercept form is y = mx + b, so to turn that equation into slope-intercept you'll need to get y alone
4x - 8y = 8 --- subtract 4x
-8y = 8 - 4x --- divide by -8
y = -1 + (1/2)x --- reorder to match "mx + b"
y = (1/2)x - 1
in y = mx + b, "m" is the slope and "b" is the y-intercept. so for part B, your slope is (1/2) and your y-intercept is (-1). take the sign with you.
for part C, you'll need to know point-slope form: (y - y1) = m(x - x1)
you'll also need to be aware that "perpendicular" lines have a slope that is the opposite reciprocal of the original line.
the original slope is (1/2). change the sign to negative and form a reciprocal: your new slope is -2. plug that into your point-slope form
(y - y1) = m(x - x1)
(y - y1) = (-2)(x - x1)
and lastly, plug in your given point: (1, 2)
y - 2 = (-2)(x - 1)
so, just to look a little neater without all of the work:
A) y = (1/2)x - 1
B) m = (1/2), b = -1
C) y - 2 = (-2)(x - 1)
Hey there!
The base angles theorem converse states if two angles in a triangle are congruent, then the sides opposite those angles are also congruent. The Isosceles Triangle Theorem states that the perpendicular bisector of the base of an isosceles triangle is also the angle bisector of the vertex angle.
Let me know if you are still confused and need a better explination :)
Have a great day!
