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DaniilM [7]
3 years ago
14

Listed are the heights of 15 players in inches on a basketball team. Fill in the table according to the data

Mathematics
2 answers:
Rus_ich [418]3 years ago
7 0
You have to show us the heights in order to solver the tables data
worty [1.4K]3 years ago
4 0
Well there is a problem with the question, which is we would need to know the data as well as the units being used in the table

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T -10 -9 -8-7-6-5-4-3-2-1. 0 1 2 3 4 5 6 7 8 9
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The correct answer is C !
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Anna11 [10]

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52

Step-by-step explanation:

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Solve for y: 1/2(4y+6)=4-2(y-6)/3​
gizmo_the_mogwai [7]

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A cylindrical container has a radius of 0.3 meter and a height of 0.75 meter. The container is filled with kerosene. The density
saveliy_v [14]

Answer:

172.83 kg

Step-by-step explanation:

A cylindrical container has a radius (r) of 0.3 meter and a height (h) of 0.75 meter and density of 815 kg/m³.

The density of a substance is the mass per unit volume, it is the ratio of the mass of a substance to the volume occupied. The density is given by the formula:

Density = Mass / volume

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V = πr²h

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6 0
2 years ago
Exhibit B: A restaurant has tracked the number of meals served at lunch over the last four weeks. The data shows little in terms
Mekhanik [1.2K]

Answer:

Option E is correct.

The expected number of meals expected to be served on Wednesday in week 5 = 74.2

Step-by-step Explanation:

We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.

Week

Day 1 2 3 4 | Total

Sunday 40 35 39 43 | 157

Monday 54 55 51 59 | 219

Tuesday 61 60 65 64 | 250

Wednesday 72 77 78 69 | 296

Thursday 89 80 81 79 | 329

Friday 91 90 99 95 | 375

Saturday 80 82 81 83 | 326

Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952

Total number of meals served at lunch on Wednesdays over the 4 weeks = 296

Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443

Total number of meals expected to be served in week 5 = 490

Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3

Checking the options,

74.3 ≈ 74.2

Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2

Hope this Helps!!!

8 0
3 years ago
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