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Gnoma [55]
3 years ago
14

Let x^2+2x-15 =0 use quadratic formula to find the roots. (roots are whole numbers)

Mathematics
1 answer:
Leviafan [203]3 years ago
4 0
Hello!

We have:

X^2 + 2x-15 = 0

Where:

a = 1
b = 2
c = -15

Delta = b^2 -4.a.c

D = 2^2 - 4.1.(-15)

D = 4 + 60

D = 64

We know,

x = [ -b+/-Raiz(delta)]/2a

x = [ -2 +/- Raiz(64)]/2

x = [-2 +/- 8]/2

Then,

x' = (-2-8)/2 <=> -5

And

x" = (-2+8)/2 <=> 3
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3 years ago
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Answers:

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Pick whichever form you prefer.

=============================================================

Explanation:

The vertex is the highest point in this case, which is located at (1,8).

In general, the vertex is (h,k). So we have h = 1 and k = 8.

One root of this parabola is (-1,0). So we'll plug x = -1 and y = 0 in as well. As an alternative, you can go for (x,y) = (3,0) instead.

Plug those four values mentioned into the equation below. Solve for 'a'.

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Expanding that out gets us the following

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Step-by-step explanation:


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