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Troyanec [42]
3 years ago
15

What is the value of the leading coefficient a, if the polynomial function P(x) = a(x + b)2(x − c) has a multiplicity of 2 at th

e point (−1, 0) and also passes through the points (7, 0) and (0, −14)?
2
Mathematics
1 answer:
kirill115 [55]3 years ago
6 0
If the polynomial function P(x) = a(x + b)^2(x-c) has a multiplicity of 2 at the point (−1, 0) then the factor (x-(-1))=(x+1) twice enters the polynomial representation. So, you have known one part of the left side of the polynomial function that is P(x) = a(x + 1)^2(x-c).

If polynomial function passes through the point (7,0), then 0 = a(7+ 1)^2(7-c) and since a\neq 0 you have that c=7.

At last, if polynomial function passes through the point (0,-14), then -14 = a(0+ 1)^2(0-7) and -14=-7a, so a=2.
Answer: a=2.



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---------

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-----------------

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