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natita [175]
2 years ago
6

What is complement of cot 30°?​

Mathematics
1 answer:
Virty [35]2 years ago
5 0

Step-by-step explanation:

cot ( 90⁰ - 30⁰ )

cot (90 - √3)

√3 - 90

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Question 1-3
KATRIN_1 [288]

Answer:

  1/3

Step-by-step explanation:

The average rate of change of a function f(x) on an interval [a, b] is given by the formula ...

  rate of change = (f(b) -f(a))/(b -a)

__

For the given function and interval, this is ...

  (log₂(4·8) -log₂(4·2))/(8 -2) = (5 -3)/(6) = 1/3

The average rate of change is 1/3.

_____

In the attached graph, the line between the points at the ends of the interval can be seen to have a rise of 1 for a run of 3. Its slope is 1/3.

8 0
2 years ago
If 1,000 gallons of oil cost $4,861, what is the cost of 35 gallons
Paul [167]

Answer:

$170.14

Step-by-step explanation:

4,861 / 1,000 = $4.861 per gallon

35 x $4.681 = $170.135, so you need to round up to the nearest penny

6 0
3 years ago
Read 2 more answers
Find the median of the following numbers: 195, 230, 200, 226​
BlackZzzverrR [31]

Answer: 213

Step-by-step explanation: The median is the middle number

in the data set when the data set is written from least to greatest.

So let's start with writing ur data set from least to greatest.

So we have 195, 200, 226, 230.

Notice that there are two middle numbers.

If there are two middle numbers in the data set,

we find the median by taking their average.

In other words, we add the two middle numbers and divide by two.

So we have 200 + 226/2 or 426/2 which is 213.

3 0
3 years ago
Solve for m and simplify: 30/4=m/6
Zarrin [17]

Answer:

m=45

Step-by-step explanation:

4 0
3 years ago
1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno
Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, H_0 : \mu = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, H_1 : \mu\neq 100  {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

               T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ N(0,1)

where, Xbar = sample mean score = 113

              s = population standard deviation = 15

             n = sample of students = 144

So, test statistics = \frac{113-100}{\frac{15}{\sqrt{144} } }

                             = 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0
3 years ago
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