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kenny6666 [7]
4 years ago
13

Which statement is correct?

Mathematics
1 answer:
vfiekz [6]4 years ago
8 0

Answer:

(2.06*10^{-2})( 1.88*10^{-1}) < \frac{7.69*10^{-2}}{2.3*10^{-5}}

Step-by-step explanation:

Verify each statement

Part 1) we have

(2.06*10^{-2})( 1.88*10^{-1}) < \frac{7.69*10^{-2}}{2.3*10^{-5}}

<u><em>Solve the left side</em></u>

(2.06*10^{-2})( 1.88*10^{-1})=(2.06*1.88)*10^{-2-1}

(3.8728)*10^{-3}

<u><em>Solve the right side</em></u>

\frac{7.69*10^{-2}}{2.3*10^{-5}}=\frac{7.69}{2.3}*10^{-2+5}

3.3435*10^{3}

substitute in the inequality

(3.8728)*10^{-3} < 3.3435*10^{3}

0.0038728 < 3,343.5  -----> is true

therefore

The statement is correct

Part 2) we have

(2.06*10^{-2})( 1.88*10^{-1}) \geq \frac{7.69*10^{-2}}{2.3*10^{-5}}

<u><em>Solve the left side</em></u>

(2.06*10^{-2})( 1.88*10^{-1})=(2.06*1.88)*10^{-2-1}

(3.8728)*10^{-3}

<u><em>Solve the right side</em></u>

\frac{7.69*10^{-2}}{2.3*10^{-5}}=\frac{7.69}{2.3}*10^{-2+5}

3.3435*10^{3}

substitute in the inequality

(3.8728)*10^{-3} \geq 3.3435*10^{3}

0.0038728 \geq 3,343.5 -----> is not true

therefore

The statement is not correct

Part 3) we have

(2.06*10^{-2})( 1.88*10^{-1}) > \frac{7.69*10^{-2}}{2.3*10^{-5}}

<u><em>Solve the left side</em></u>

(2.06*10^{-2})( 1.88*10^{-1})=(2.06*1.88)*10^{-2-1}

(3.8728)*10^{-3}

<u><em>Solve the right side</em></u>

\frac{7.69*10^{-2}}{2.3*10^{-5}}=\frac{7.69}{2.3}*10^{-2+5}

3.3435*10^{3}

substitute in the inequality

(3.8728)*10^{-3} > 3.3435*10^{3}

0.0038728 > 3,343.5 -----> is not true

therefore

The statement is not correct

Part 4) we have

(2.06*10^{-2})( 1.88*10^{-1}) = \frac{7.69*10^{-2}}{2.3*10^{-5}}

<u><em>Solve the left side</em></u>

(2.06*10^{-2})( 1.88*10^{-1})=(2.06*1.88)*10^{-2-1}

(3.8728)*10^{-3}

<u><em>Solve the right side</em></u>

\frac{7.69*10^{-2}}{2.3*10^{-5}}=\frac{7.69}{2.3}*10^{-2+5}

3.3435*10^{3}

substitute in the equation

(3.8728)*10^{-3} = 3.3435*10^{3}

0.0038728 = 3,343.5 -----> is not true

therefore

The statement is not correct

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