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timofeeve [1]
4 years ago
13

If you have 5 protons and 6 neutrons, how many electrons would you add to make a neutral atom?

Mathematics
1 answer:
Goshia [24]4 years ago
5 0

Answer:

The correct option is;

5 electrons

Step-by-step explanation:

The charge of the proton is equal to 1.602 × 10⁻¹⁹C while the charge of one electron is -1.602 × 10⁻¹⁹C

Therefore, given that the atom is to be electrically neutral, we have;

The initial charge of the atom = 5 × 1.602 × 10⁻¹⁹C = 8.01 × 10⁻¹⁹C

The charge of the added electron + The charge of the present proton = 0

Therefore;

The charge of the added electron + 8.01 × 10⁻¹⁹C = 0

The charge of the added electrons = 0 - 8.01 × 10⁻¹⁹C = -8.01 × 10⁻¹⁹C

The charge of one electron = -1.602 × 10⁻¹⁹C

The number of electrons = The charge of the added electrons/(The charge of one electron)

The number of electrons = -8.01 × 10⁻¹⁹C/(-1.602 × 10⁻¹⁹C) = 5 electrons

The number of electrons to be added = 5 electrons.

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The <em>correct answer</em> is:


To draw arcs of a given size.


Explanation:


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What number would represent the outlier in the following set of data?
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Answer:

An outlier is the number that is much smaller or larger than the other numbers.

In this case it is 29 :)

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Find the radius of a circle with the circumference of 28.27 km. Explain your answer
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radius= 4.5

Step-by-step explanation:

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The City of Irvine upgraded a bicycle lane in a section of road to have a physical barrier between the cyclists as opposed to ju
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Answer:

The p-value of the test is 0 < 0.05, which means that there is significant evidence to conclude that more people utilize the bike lane after the change.

Step-by-step explanation:

Before the upgrade, on any given day, it was known that the section of road saw an average of 350 unique cyclists. Test if more people are using now.

At the null hypothesis, we test if the same number of people is still using, that is, the mean is 350. So

H_0: \mu = 350

At the alternate hypothesis, we test if this mean increased, that is:

H_1: \mu > 350

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

350 is tested at the null hypothesis:

This means that \mu = 350

After the upgrade, they took a random sample of 35 days in the year and counted the number of unique cyclists each day. The average was 405 cyclists with a standard deviation of 25.

This means that n = 35, X = 405, s = 25.

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{405 - 350}{\frac{25}{\sqrt{35}}}

t = 13.02

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 405, which is a right-tailed test with t = 13.02 and 35 - 1 = 34 degrees of freedom.

Using a t-distribution calculator, this probability is of 0.

The p-value of the test is 0 < 0.05, which means that there is significant evidence to conclude that more people utilize the bike lane after the change.

8 0
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