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Llana [10]
4 years ago
15

Plz help and explain :)))

Mathematics
2 answers:
Arte-miy333 [17]4 years ago
8 0
Hello there!


See picture below...


Let me know if you have more questions about the answer :)

As always, it is my pleasure to help students like you!


guapka [62]4 years ago
6 0
Solve
z^2-16z=-9

Transpose -9 to the left to end up with the standard form of the quadratic equation:
z^2-16z+9=0
Since it does not appear to have rational roots, we proceed with the quadratic formula, where a=1, b=-16, c=9
and substitute in the quadratic formula:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
=\frac{16\pm\sqrt{(-16)^2-4*1*9}}{2}
=\frac{16\pm\sqrt{256-36}}{2}
=8\pm\sqrt{55}
i.e.
z=8+sqrt(55) or 8-sqrt(55)
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Which of the following values is a zero of the expression x²+9x²-x-105
Reika [66]

Answer:

x=7

x=5

x=−3

Step-by-step explanation:

0-(x^3-9*x^2-x+105)=0  

Step by step solution :

STEP

1

:

Equation at the end of step 1

 0 -  ((((x3) -  32x2) -  x) +  105)  = 0  

STEP

2

:

Checking for a perfect cube

2.1    -x3+9x2+x-105  is not a perfect cube

Trying to factor by pulling out :

2.2      Factoring:  -x3+9x2+x-105  

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  x-105  

Group 2:  -x3+9x2  

Pull out from each group separately :

Group 1:   (x-105) • (1)

Group 2:   (x-9) • (-x2)

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3 years ago
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