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Marysya12 [62]
3 years ago
11

How do I put 3(x+7) in distributive property

Mathematics
1 answer:
IRISSAK [1]3 years ago
3 0
It already is in disruptive property but to solve it using distributive property it become 3x+21.
You might be interested in
Tim answered all the questions on his math test but got 010 answers wrong. He received 44 points for every correct answer, and t
yKpoI14uk [10]
44x is the way the points are calculated. In order to find out the amount of questions there needs to be a constant, 10 which represents the number of wrong questions, and a variable, x which represents the number of correct questions. You have to know that if wrong questions were counted, he would have 440 points just for the 10 wrong questions. Next you have to add the amount of correct questions and their corresponding points. The numbers that you get should be put together with the wrong questions. The points for the wrong questions don't count but the questions do. When you find the number, (I don't know what it is so I will use x but you will have to find out what it is) you will add x, the number of correct questions to the 10 incorrect questions and then you will have 10+x for the questions. You will need to use 44x to find out the number of points and once you have done that, you use this equation to average the points over the total questions: 44x/10+x
5 0
3 years ago
A sales man is paid a basic wage of $225 per week. In addition he is paid a commission of 3% on the value of goods he sells abov
mihalych1998 [28]

Answer:

Commission = $375

Total earnings = $600

Step-by-step explanation:

He gets 3% of any sale he makes above %5500 which means his commission received on this sale is;

= 3% * $12500

= \frac{3}{100} * $12500

= 3* 125

= $375

This means his total earnings for the week will be the basic wage plus his commission

$225 + $375

= $600

3 0
4 years ago
Number 1d please help me analytical geometry
lesantik [10]
For a) is just the distance formula

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ x}}\quad ,&{{ 1}})\quad 
%  (c,d)
B&({{ -4}}\quad ,&{{ 1}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\sqrt{8} = \sqrt{({{ -4}}-{{ x}})^2 + (1-1)^2}
\end{array}
-----------------------------------------------------------------------------------------
for b)  is also the distance formula, just different coordinates and distance

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ -7}}\quad ,&{{ y}})\quad 
%  (c,d)
B&({{ -3}}\quad ,&{{ 4}})
\end{array}\ \ 
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
4\sqrt{2} = \sqrt{(-3-(-7))^2+(4-y)^2}
\end{array}
--------------------------------------------------------------------------
for c)  well... we know AB = BC.... we do have the coordinates for A and B
so... find the distance for AB, that is \bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ -3}}\quad ,&{{ 0}})\quad 
%  (c,d)
B&({{ 5}}\quad ,&{{ -2}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=\boxed{?}

\end{array}

now.. whatever that is, is  = BC, so  the distance for BC is

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
B&({{ 5}}\quad ,&{{ -2}})\quad 
%  (c,d)
C&({{ -13}}\quad ,&{{ y}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=BC\\\\
BC=\boxed{?}

\end{array}

so... whatever distance you get for AB, set it equals to BC, BC will be in "y-terms" since the C point has a variable in its ordered points

so.. .solve AB = BC for "y"
------------------------------------------------------------------------------------

now d)   we know M and N are equidistant to P, that simply means that P is the midpoint of the segment MN

so use the midpoint formula

\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
M&({{-2}}\quad ,&{{ 1}})\quad 
%  (c,d)
N&({{ x}}\quad ,&{{ 1}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=P
\\\\\\


\bf \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=(1,4)\implies 
\begin{cases}
\cfrac{{{ x_2}} + {{ x_1}}}{2}=1\leftarrow \textit{solve for "x"}\\\\
\cfrac{{{ y_2}} + {{ y_1}}}{2}=4
\end{cases}

now, for d), you can also just use the distance formula, find the distance for MP, then since MP = PN, find the distance for PN in x-terms and then set it to equal to MP and solve for "x"


7 0
4 years ago
Nerissa paid a total of $8 for 4 packs of pencils she purchased from the convenience store. Let p represent the cost of one pack
BARSIC [14]

Answer: 4*p=8

Step-by-step explanation:

<em>You can use inverse operation to answer this equation.</em>

  • <em>write out you problem: 4 x p =8</em>
  • <em>The inverse of multiplication is division</em>
  • <em>you do 4/4 which gives you one but the 4 will cancel itself out</em>
  • <em>Do 8/4 which gives you 2</em>
  • <em>under the equation write p = 2</em>
  • <em>And be sure to line the p up with the p, the equal sign with the equal sign, and  the 2  stays where it is ( which should be already lined up with the 8)</em>
3 0
3 years ago
Logs are stacked in a pile. The bottom row has 50 logs and next to bottom row has 49 logs. Each row has one less log than the ro
Mars2501 [29]

Answer:

46 logs on the 5th row.

Step-by-step explanation:

Number of logs on the nth row is

n =  50 - (n-1)

 n = 51 - n    (so on the first row we have  51 - 1 = 50 logs).

So on the 5th row we have 51 - 5 = 46 logs.

8 0
3 years ago
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