Question

Solve 11b^2-9=-68 using the square root method

Answer 1

Answer:

b=i*$\sqrt{\frac{59}{11} }$ or -i*$\sqrt{\frac{59}{11} }$

Step-by-step explanation:

11b^2-9=-68

11b^2=-59

b^2=-59/11

b=i*$\sqrt{\frac{59}{11} }$ or -i*$\sqrt{\frac{59}{11} }$

"i" in this case is an imaginary number, equal to $\sqrt{-1\\}$

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