Explain how you know 21/100 is greater than 1/5
1 answer:
This problem can be solved using equivalent fractions. The first step in resolving this problem is to realize that fractions are best compared when they both have the same denominator. In this case, I will choose to make that common denominator 100. There is no need to rewrite the fraction as the denominator for this fraction is already 100. The fraction
. This is achieved by multiplying both the numerator and denominator by 20. Now that the two fractions have the same denominator, we can easily see that
is greater than
because it is greater than its equivalent fraction.
You might be interested in
The dimensions of the rectangle are length 156 m and a width of 65m, and a perimeter P = 442m
<h3>How to find the dimensions of the rectangle?</h3>For a rectangle of length L and width W, the diagonal is:
Here we know that the diagonal is 169m.
And the ratio of the length to the width is 12:5
This means that:
W = (5/12)*L
Replacing all that in the diagonal equation:
So the length is 156 meters, and the width is:
W = (5/12)*156 m = 65m
Finally, the perimeter is:
P = 2*(L + W) = 2*(156 m + 65m) = 442m
If you want to learn more about rectangles:
#SPJ1