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Rainbow [258]
3 years ago
6

Tom has 28 milk chocolates and emily has 24 dark chocolates they have to divide these chocolates into small packets that each ha

ve the same number of dark chocolates and the same number of milk chocolates
The maximum number of packets they can make is ___To make the maximum number of packets, each packet should have___ milk chocolates and ___
dark chocolates.​
Mathematics
2 answers:
nignag [31]3 years ago
4 0

Answer: the maximum number of packets they can make i 4 packets to make the maximum number of packets, each packet should have 7 milk chocolates and 6 dark chocolates. If that does not work then there can be 2 packets with 14 milk chocolates and 12 dark chocolates.

Step-by-step explanation:

This is hurting my brain ngl

Hope this helps though ;)

natima [27]3 years ago
4 0

Answer:

The maximum number of packets they can make is 4

Each packet should have 7 milk chocolate and 6 dark chocolate

Step-by-step explanation:

The GCF of 28 and 24 is 4

1,2,4,7,14,28

1,2,3,4,6,8,24

7x4=28        6x4=24

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What is 8x + 16 + xy + 2y as factor each expression completely.
liraira [26]

Answer:

( x + 2 ) ( 8 + y )

Step-by-step explanation:

8 0
3 years ago
In geometry, Heron's formula (sometimes called Hero's formula), named after Hero of Alexandria, gives the area of a triangle by
uysha [10]

Answer:

C) 6.495\: ft^2

Step-by-step explanation:

a = 7 ft, b = 3 ft, c = 5 ft (Given)

Therefore, a + b + c = 7 + 3 + 5 = 15 ft

Let's calculate semi Perimeter of the triangle which is given by s

s =\frac{a+b+c}{2}=\frac{15}{2} = 7.5 \: ft

Now, by Heron's formula, area of triangle ABC is given as:

A(\triangle ABC) =\sqrt{s(s-a) (s-b)(s-c)}

\therefore A(\triangle ABC) =\sqrt{7.5(7.5-7) (7.5-3)(7.5-5)}

\therefore A(\triangle ABC) =\sqrt{7.5(0.5) (4.5)(2.5)}

\therefore A(\triangle ABC) =\sqrt{42.1875}

\therefore A(\triangle ABC) =6.49519053

\therefore A(\triangle ABC) =6.495\: ft^2

8 0
3 years ago
I NEED HELP!!! PLEASE!!!!!!!!!!!!!!!!!
ale4655 [162]
The awnser to ur question is A because take 2.3 time 3 and get 6.9 and then add the 108 and -3 and get 105
3 0
3 years ago
The area of a rectangle is 56 cm. The length is 2 cm more than x and the width is 5 cm less than twice x. Solve for x. Round to
sashaice [31]
(2 + x) x (2x-5) = 56

(2+x)(2x-5)=56

2x² - x - 10 = 56
           +10    +10

2x² - x = 66 

2x² - x - 66 = 0

x = 6 

2(6)² - (6) = 66
2(36) - 6 = 66
72 - 6 = 66
66 = 66

7 0
3 years ago
How many solutions are there to the equation 3x-2y=-60?
Lesechka [4]

Answer:

No solutions

Step-by-step explanation: BTW put / instead of over

when you put it in y=mx+b form you get:

y=2 over 3x+30

x=-20+2y over 3

you then put:

x=-20+2(2 over 3x+30) over 3

and get no solution!

8 0
4 years ago
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