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earnstyle [38]
4 years ago
11

2. Another machine is used to make 10 mm long bolts. For this machine, the bolts must have an error of less than 0.1 mm to be ac

cepted. This can be represented by |x – 10| < 0.1.
a. Write this inequality as a compound inequality without absolute value bars. b. Solve the compound inequality.
c. Graph the solutions on a number line.
d. What do the solutions of the inequality mean for the bolt?
Mathematics
1 answer:
wlad13 [49]4 years ago
6 0
Part AAnswer: -0.1 < x-10 < 0.1
Use the rule |x| < k leads to -k < x < k for some positive number k

Part BAnswer: 9.9 < x < 10.1
Add 10 to all three sides of -0.1 < x-10 < 0.1


Part C
Draw out a number line. Plot open circles at 9.9 and 10.1 on the number line. Shade the region between the open circles. The open circles indicates "do not include this point as part of the solution set"

Part D
The solution 9.9 < x < 10.1 means that anything between 9.9 and 10.1 is accepted as a bolt length (even if the exact measurement isn't 10 mm on the dot). The length 9.9 is not allowed; neither is 10.1


Hope this helped! (:
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Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x3 − 6x2 − 15x + 2 (a) Find the interval on which
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Answer:

a) (-\infty, -1) \cup (5, \infty)

b) (-1,5)

Step-by-step explanation:

The first step to solve this question is finding the roots of the derivative of x.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

f(x) = x^{3} - 6x^{2} - 15x + 2

So

f'(x) = 3x^{2} - 12x - 15

Finding the roots:

3x^{2} - 12x - 15 = 0

Simplifying by -3

x^{2} - 4x - 5 = 0

So a = 1, b = -4, c = -5

Then

\bigtriangleup = (-4)^{2} - 4*1*(-5) = 36

x_{1} = \frac{-(-4) + \sqrt{36}}{2} = 5

x_{2} = \frac{-(-4) - \sqrt{36}}{2} = -1

So the function can be divided in three intervals.

They are:

Less than -1

Between -1 and 5

Higher than 5

In which it increases and which it decreases?

Less than -1

Lets find the derivative in a point in this interval, for example, -2

f'(x) = 3x^{2} - 12x - 15

f'(-2) = 3*(-2)^{2} - 12*(-2) - 15 = 21

Positive.

So in the interval of (-\infty, -1), the function increases.

Between -1 and 5

Will choose 0.

f'(x) = 3x^{2} - 12x - 15

f'(0) = 3*(0)^{2} - 12*(0) - 15 = -15

Negative.

So in the interval of (-1,5), the function decreases.

Higher than 5

Will choose 6.

f'(x) = 3x^{2} - 12x - 15

f'(6) = 3*(6)^{2} - 12*(6) - 15 = 21

Positive

So in the interval of (5, \infty), the function increases.

(a) Find the interval on which f is increasing.

Using interval notation

(-\infty, -1) \cup (5, \infty)

b) Find the interval on which f is decreasing.

(-1,5)

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