Answer:
Each tray has 5 colours and one of the colour on the tray is purple. Hence 1/5 of the colours on the tray is purple and thus 1/5 of the colours on the 20 trays is purple. The fraction of colours on the trays will not change. If written out logically, 20 purples out of 100 colours in total on the trays will also given the fraction 1/5.
<span><span> <span>Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........</span></span><span><span><span>A.x² - x - 4 = 0</span><span>B.x² + 5x - 4 = 0</span><span>C.x² - x + 4 = 0</span></span><span><span>D.x² + x + 4 = 0</span><span>E.x² - 5x - 4 = 0</span></span></span><span>Jawaban : A
Penyelesaian :
Akar-akar persamaan lama : x1 dan x2
Akar-akar persamaan baru : xA dan xB
xA = 2x1 - 1
xB = 2x2 - 1
xA + xB = (2x1 - 1) + (2x2 - 1)
= 2 (x1 + x2) - 2
= 2 () - 2
= 3 - 2
xA + xB = 1
xA . xB = (2x1 - 1) (2x2 - 1)
= 4 x1.x2 - 2(x1 + x2) + 1
= 4.(-) - 2() + 1
= -2 - 3 + 1
xA . xB = -4
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
x² - x - 4 = 0
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Step-by-step explanation:
first identify the common difference
The first term which i will define by u⁰=-27
u¹=u⁰+(1)d where d is the common difference and u¹ is the second term
u¹=-27+d
-11=-27+d
d=27-11=16
The 72nd term would be u⁷¹ since we started from u⁰ as our first term:
Use the explicit relation given by:
u(n)=u⁰+(n)d
u(71)=-27+71(d)
u⁷¹=-27+71(16)
u⁷¹=-27+1136
u⁷¹=1109
35 + 15 x 4 = 60. Paola read 60 pages in total.
Answer:
1:4
Step-by-step explanation:
3:12
((3×1):(3×4))
=1:4
(would love if you could mark me the brainliest :))
