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Mariulka [41]
3 years ago
5

I would like assistance, please.

Mathematics
1 answer:
makvit [3.9K]3 years ago
3 0
Answers:
(2) Option (B) 4
(3) The answer is: +1

Explanations:
(2) The plus sign in the limit indicates that it is the right hand limit. So we have to approach to 2 from the right side of the graph. When we do that, we see the value of y = +4. Hence the correct option is (B) 4

NOTE: Although the question seems complex because there is slope involved but in this particular case, the examiner is concerned about the right hand limit.

(3) The minus sign in the limit indicates that it is the left hand limit. So we have to approach to 3 from the left side of the graph. When we do that, we see the value of y = +1. Hence the correct answer is +1.
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3n + 3 = -369
3n = -366
n = -122

so the three consecutive integers are : -124 ; -123 ; -122
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et f(x) = x + |2x − 3|. Find all solutions to the equation f(x) = 12. (Enter your answers as a comma-separated list. If an answe
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Answer:

1. {5,-9}

2.{4}

3.{9/2}

Step-by-step explanation:

The equation f(x)=x+\lvert 2x-3 \rvert=12 can be solved as follows:

x+\lvert 2x-3 \rvert =12\,\,\,\text{(given equation)}

\lvert 2x-3 \rvert =12-x

2x-3=12-x\,\,\text{or}\,\,2x-3=-(12-x)

3x=15\,\,\text{or}\,\,\x=-9

Then, the solutions of the equation are x=5, x=-9.

Now, if g(x)=5x-3+\lvert x+4\rvert, we can solve the equation g(a)=4a+9 as follows:

5a-3+\lvert a+4 \rvert =4a+9

\lvert a+4\rvert =4a+9-5a+3

a+4 =-a+12\,\,\text{or}\,\,a+4=-(-a+12)

2a=8\,\,\text{or}\,\,4=12

So, the unique solution of this last equation is a=4

The last equation is h(x-1)=x-3, where h(x)=\lvert x \rvert -2x+5.. To solve this equation we can proceed as follows:

h(x-1)=x-3

\lvert x-1\rvert -2(x-1)+5=x-3

\lvert x-1 \rvert -2x+2+5=x-3

\lvert x-1\rvert =3x-10

x-1=3x-10\,\,\text{or}\,\,x-1=-(3x-10)

-2x=-9\,\,\text{or}\,\,4x=11

x=9/2\,\,\text{or}\,\,x=11/4

But, x=11/4 is not a solution of this equation. So the unique solution is x=9/2.

8 0
3 years ago
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